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Aim
To discover the accurate concentration of a sample of sulphuric (VI) Acid. It is thought to have a concentration between 0.05 and 0.15 mol dm-3. This is to be done by neutralising the acid with sodium carbonate using a titration.
Theoretical Background
The reaction between Sulphuric Acid and Sodium Carbonate is a neutralisation. Sulphuric acid is a strong acid(1) . This means that it is a powerful proton, H+ donor and that it is completely in the form of ions when in dilute solution. Acids and bases are classified depending on the extent to which they form ions when dissolved in water. Sodium Carbonate is a weak base. It is a proton, H+ acceptor, however it is only a moderate one and ionisation is partially complete.
The formula for this reaction is as follows:
Sulphuric Acid + Sodium Carbonate = Sodium Sulphate + Water + Carbon Dioxide
H2SO4(aq) + Na2CO3(aq) = Na2SO4(aq) + H2O(l) + CO2(aq)
In order to determine the concentration of the Sulphuric Acid it can be......
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Title: Finding Out How Much Acid Is In A Solution
Approximate Word Count: 2818
Approximate Pages: 12 (250 words per double-spaced page)
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